eⁱπ + 1 = 0
∫₀^∞ e⁻ˣ² dx = √π/2
Σ 1/n² = π²/6
φ = (1+√5)/2
∇ × E = -∂B/∂t
det(A-λI) = 0
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Nonprofit Math Community in Tashkent

The Roots of π

Unlocking the potential of teenagers through the power of mathematics.Join our vibrant community of problem solvers.

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∫₀^∞ e^(-x²) dx = √π/2
eⁱᵖ + 1 = 0
∑ 1/n² = π²/6
φ = (1+√5)/2
∇×E = -∂B/∂t
ax² + bx + c = 0
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At The Roots of PI, we are passionate about unlocking the potential of teenagers through the power of mathematics. We foster critical thinking and problem-solving skills through engaging events, challenges, and a supportive community.

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